Matthew has twice as many stickers as david. how many stickers must matthew give david so that they each will have 120 stickers?

M is Matt's sticker count, D is David's:  

The equations:  

The average sticker count has to be 120, so:  

(M + D) / 2 = 120  

Matt has twice as many as David:  

M = 2D  

Substitute for M in the average, so:  

(2D + D) / 2 = 120  

Solving you get:  

3D = 240  

D = 80 and 120 - 80 is 40, so Matt has to give him 40 stickers.

Hope this helps :)

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

answer: x

step-by-step explanation: