Nparallelogram lmno, mp = 21 m, lp = (y + 3) m, np = (3y – 1) m, and op = (2x – 1) m. what are the values of x and y? x = 10, y = 1 x = 10, y = 2 x = 11, y = 1

The value of x = 11  and y = 2

Step-by-step explanation:

Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.

We have to find values of x and y.

Let P be the point of intersection of diagonals OM and LN.

In a parallelogram diagonal  bisects at right angles  and point of intersection divide diagonal in equal parts.

Thus, OP = MP and LP = PN

OP = MP , substitute the values, we get,

(2x-1) =  21

⇒ 2x = 22

⇒  x = 11

LP = PN , substitute the values, we get,

y + 3 = 3y -1

⇒  3y - y = 4

⇒  2y = 4

⇒ y = 2  

Thus, the value of x = 11  and y = 2

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step-by-step explanation: