50 pls with attached and show your work

Step-by-step explanation:

∠2 is a right angle, so ∠3 is complementary to the 39° angle shown. It is ...

  ∠3 = 90° -39° = 51°

ΔDAB is isosceles, so ∠DBA ≅ ∠3 and ∠1 ≅ 39°.

If you're starting completely from scratch, you might go to the trouble to show ΔABC ≅ ΔADC, hence AC is a bisector of angles A and C. If X is where the diagonals cross, then you can show ΔABX ≅ ΔADX and ∠2 is 90°.

I prefer to start with the fact that the diagonals of a (symmetrical) kite cross at right angles. That makes all the triangles right triangles, so the angles are easily found, given any one of them. (Acute angles of a right triangle are complementary.) Of course, the triangles on one side of the line of symmetry (AC) are congruent to those on the other side.

answer: plz put a pic in so i can answer it

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!