Find the area and perimeter of the parallelogram a) a=26.6cm2, p=26cm b) a=37.72cm2, p=26cm c) a=15.58cm2, p=26.6cm d) a=34.96cm2, p=26.6cm will give brailyest! !

D

Step-by-step explanation:

To find the area of a parallelogram, multiply base*height where the height is the perpendicular to the base.

Here the base is 9.2 cm. The perpendicular height is 3.8 cm.

The area is 9.2*3.8= 34.96 square cm.

Since only D has this option for the area, then the perimeter must be 26.6 cm.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.