answer: 3/4 of an hour
step-by-step explanation: take 36 divide it by 48
option a, c,d are correct.
from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have
therefore, by rhs rule,δtzb ≅δszb
by cpctc, sz≅tz
also, from δctz and δasz,
by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz
also,from δasz and δzsb,
by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb
hence, option a, c,d are correct.
b: ∠x = 28.6°, ∠y = 31.2°, ∠z = 120.2°
this is one of those questions where "test taking skill" is all you need. the only answer that has angles that sum to 180° is the one shown above. the remaining choices do not describe the angles of a triangle.
if you want to do more work than simply adding the offered numbers, you can also check them against the law of sines. it should be true that
x/sin(x) = y/sin(y) = z/sin(z)
and all of these ratios must be greater than 15, the longest side length.
if you want to solve the triangle from scratch, i'd suggest solving for the largest angle using the law of cosines.
z² = x² +y² -2xy·cos(z)
z = arccos((x² +y² -z²)/(2xy)) = arccos(-75.11/149.4) = 120.182°
now you can find y from the law of sines
y = arcsin(y/z·sin(z)) = 31.242°