Step 1: Draw an arc from each of these points of intersection so that the arcs intersect in the interior of the angle. The compass needs to stay open the same amount throughout this step.
Step 2: Draw the ray from the vertex of the angle to the intersection of the two arcs drawn during the previous step.
The steps for constructing the bisector of an angle using only a compass and a straightedge are as follows,
Step 1 :
Place the compass on the vertex of the angle.
Step 2 :
Set the compass on the vertex and adjust it to any length.
Step 3 :
Draw arcs on both sides ( rays ) of the angle.
Step 4 :
From the intersection of arcs and sides in both sides draw another arcs ( Without changing the span of compass ) between the sides of the angle such that we get intersection of arcs.
Step 5 :
With help of straightedge, join the vertex and the intersection point we get in previous step.
sorry:( that looks hard hope you find the answer :)
position your compass at point A and using the same distance mark arcs on line AB(mark the point it meets the line D)and AC(mark the meeting point of the arc and the line E).Place your compass at D and draw an arc at the middle of the angle,using the same measurements position your compass at point E and draw an arc.Where the two arcs meet label F using a ruler draw a straight line from F to meet point A.
Note;the width of the compass when making the arcs should be the same always
The correct answer is
Just took the test.
1) place the compass needle on the external point r.2) make the compass width greater than the distance from r to the given line.
3) draw an arc cutting the given line at two points.
4) mark and label the points of intersection p and q.
5) without changing the compass width, move the compass needle to q and draw another arc below the line crossing the previous arc.
6) move the compass needle to p and make an arc below the line.
7) mark and label the point of intersection s.
8) draw a line from the external point r to the point where the arcs intersect, s.
9) line rs is perpendicular to line pq and passes through the external point r.