What are the zeros of the polynomial function? f(x)=x2−12x+20 enter your answers in the boxes. the zeros of f(x) are and

Hello from MrBillDoesMath!

x = 2 and 10

Discussion:

Approach 1:

20 = (-10)*(-2) and  (-10) + (-2) = -12 the coefficients of the polynomial. Hence

x^2 -12x + 20 = ( x- 2) * ( x-10)

Approach 2:

From the quadratic formula ( a = 1, b = -12, c = 20)

x =    (  -(-12) +\- sqrt( ((-12)^2 - 4*1*20) )  /  (2 * 1)

   =    ( 12 +\- sqrt( 144-80)  ) /2

  =   (12 +\-  sqrt(64) ) /2

  =  (12 +\- 8 ) /2

x  = ( 12 + 8) /2 = 20/2 = 10

or

x = ( 12 - 8)/ 2 = 4/2 = 2

Thank you,

MrB

The zeros of the function are 2 and 10. The points are (2,0) and (10,0).

Step-by-step explanation:

To solve for the zeros, factor the polynomial function.

To solve for x, set each factor equal to 0.

x-2 = 0 so x=2

x-10 = 0 so x=10

you can't solve x because it is 2 linear equation and you only have one equation

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.