Give the coordinates for point p in the kite below without using any variables

D. (-b,0)

applying coordinate geometry practice

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1. b.

2. a.

3. c.

4. d.

5. c.

6. c.

7. a.

8. d.

9. d.

10. b.

Coordinates of P = (-b,0)

Step-by-step explanation:

Given that a kite is drawn on a cartesian graph.  The coordinates are

(0,a) (b,0) , (0,-c) and unknown coordinate for P.

We know that in a kite adjacent sides are equal.  Also diagonal cut at right angles with bisecting only one diagonal.

Here we find that the line y axis joining (0,a) and (0,-c) is the perpendicular bisector of the diagonal of x axis joining P and (b,0

Since P lies on x axis, coordinate of P (k,0) for some value k

SInce O is the mid point , we get (0,0) is the mid point of (k,0) and (b,0)

Using mid point formula we find that k =-b.

Hence coordinates of P = (-b,0)

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!