So my math teacher doesn't give us any steps to know how to do the equations. she just tells us the unit, then the vocab plus the essential question. after that she clicks to the next slide and it's just 6 examples then she tells us to do it.

question: my question is can someone show me the steps to do 2 step equations?

I personally understand what you are saying... everyone has a teacher like that at least once in their schooling.

Doing two-step equations can sometimes be tricky, even if you understand the topic pretty well. All two-step equations are: equations that require two objectives to solve for the variable (That's why it's called a two-step equation).

There are multi-step equations...but let's take one bite at a time.

First, let's establish one simple rule:

Anything you do to one side of the algebraic equation, you must do to the other side for the equation to remain true.

For example:

So, we have this just chillin' out with the . When trying to solve for a variable, this is usually not what we want. The needs to be alone for us to know what equals.

For the first step of getting alone, we can add on each side of the equation to cancel out the on the variable's side. Remember to do it on both sides of the equation!

becomes

Did you see what I did there? All I did was basically add to and . The equation remains equal, but using that simple rule, we were able to get one step closer to isolating the in the equation.

To continue...

turns into (This is because the and the cancel out.)

Now we have

This next step should look familiar to you (assuming you already know how to solve for one-step equations, I'll keep it short and sweet).

Now, since is the same as saying times , we can do the opposite of multiplication...which is division, like so:

The 's will cancel each other out and simplifies to .

Awesome! Looks like we solved our two-step equation!

In the equation: ,

Some things to remember:

Hope I was able to help you out! Have a good one, and God bless!

Also, if you are confused about something I answered, or I may be incorrect, feel free to let me know!

1

step-by-step explanation:

you are throwing one dart

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!