If triangle cde is dilated by a scale factor of 1 2 with a center of dilation at the origin, how does the area of c'd'e' compare with the area of cde?

The area of C'D'E' = 1/4 × the area of CDE

Step-by-step explanation:

Let the coordinates of triangle CDE are , and

Since, In the dilation about origin by the scale factor k,

Thus, when triangle CDE is dilated by a scale factor

Then the coordinates of triangle C'D'E' are,

, and

Since, the area of triangle C'D'E'

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srry idk

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)