Guliskhan plans to cover a certain distance by running and bicycling. she runs at a constant speed, and she bicycles at a speed of 77 meters per second (\text{m/s})(m/s). let rr represent the number of seconds that guliskhan runs and bb represent the number of seconds that she bicycles according to her plan. 3r+7b \geq 10003r+7b? 1000 according to the inequality, at what speed does guliskhan run, and what is the minimum distance that she plans to cover? guliskhan runs at a speed of \text{m/s}m/s, and plans to cover a minimum distance of meters. can guliskhan cover this minimum distance if she runs for 6060 seconds and bicycles for 9090 seconds?

A. Gulkiskhan ran at a speed 3 meters per second.

B. Minimum distance = 1000 meters.

C. No, she not cover the minimum distance if she runs for 60 seconds and bicycles for 90 seconds.

Step-by-step explanation:

Let R represent the number of seconds that Guliskhan runs and B represent the number of seconds that she bicycles .

A. We have been given that Guliskhan bicycles at a speed of 7 meters per second, so distance (in meters) bicycled by Guliskhan in B seconds will be 7B.

We have been given an inequality .

We can see that 7B represents the distance in meters bicycled by Gulkishan in B seconds.

As R represent the number of seconds that Guliskhan runs, so 3R represents the distance in meters run by her.

Since Guliskhan runs at a constant speed, so Gulkiskhan ran at a speed 3 meters per second.

B. We can see that the total distance covered by Gulkiskhan 3R plus 7B is greater than or equal to 1000, therefore, the minimum distance that she plans to cover is 1000 meters.

C. Let us substitute R=60 and B=90 in our inequality to check whether Guliskhan can cover this minimum distance or not.

Therefore, Guliskhan can not cover the minimum distance if she runs for 60 seconds and bicycles for 90 seconds.

i believe the answer is letter c) 8

step-by-step explanation: