The sum of 6 consecutive integers is 519. what is the third sequence?

X=84

Step-by-step explanation:

let x be the first integer, then

:

x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) = 519

:

6x + 15 = 519

:

6x = 504

:

x = 84

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: