How many real solutions does a quadratic equation have if its discriminant is negative?

A

Step-by-step explanation:

Discriminant is given by

If it is negative then in quadratic formula the square root part becomes negative which makes the solution complex.

so there cannot be any real solution if the Discriminant is negative or less than 0 ,

The correct option for the given question is

A

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )