Let g(x)=2x and h(x)=x2+4. find the value. (hog) (0)

4

Step-by-step explanation:

It's much easier to see the meaning if brackets are used.

h(g(x) ) = h·g(x)

What this means is that in h(x) where ever there is an x, put a g(x)

h(x) = x^2 + 4

h(g(x)) = [g(x)]^2 + 4

Now where ever you see a g(x), put 2x

h(g(x))= (2x)^2 + 4

h(g(x)) = 4x^2 + 4              

Now solve for h(g(0)) which means where ever you see a x substitute a 0.

h(g(0)) = 4*(0) + 4

h(g(0)) = 4

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