What is the additive inverse of the complex number –8 + 3i? –8 – 3i –8 + 3i 8 – 3i 8 + 3i

Step-by-step explanation:

The additive inverse of a number a is the number that, when added to a, yields zero.

(-8 + 3i) + (a + bi) = 0

(-8 + a) + (3i + bi) = 0 + 0i

(-8 + a) + (3 + b)i = 0 + 0i

therefore

-8 + a = 0 and 3 + b = 0

a = 8 and b = -3

8 – 3i

Step-by-step explanation:

The additive inverse gets you to zero

-8+3i + x = 0

Solve for x

Add 8 to each side

-8+8+3i + x = +8

3i +x = 8

Subtract 3i

3i -3i +x = 8-3i

x = 8-3i

The additive inverse is 8-3i

Negate the number

-8+3i

-(-8+3i)

8-3i

answer: do we write it

step-by-step explanation:

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula