Express 2x^2+3x/(2x+3)(x-2) - 6/x^2-x-2 as a single fraction in its simplest form.

(x + 3)/(x + 1) .

Step-by-step explanation:

2x^2 + 3x/(2x + 3)(x - 2) - 6 /x^2 - x - 2

= 2x^2 + 3x/(2x + 3)(x - 2) - 6 / (x - 2)(x + 1)

The LCM is (2x + 3)(x - 2)(x + 1) so we have

(2x^2 + 3x)(x + 1) - 6(2x + 3)          x( 2x + 3)(x + 1) - 6(2x + 3)

=        

    (2x + 3)(x - 2)(x + 1)                         (2x + 3)(x - 2)(x + 1)

       (2x + 3)(x(x + 1) - 6)           (2x + 3)(x - 2)(x + 3)

=      =           =  (x + 3)/(x + 1)

     (2x + 3)(x - 2)(x + 1)             (2x + 3)(x - 2)(x + 1)  

idk

step-by-step explanation:

idk

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right