Astock trading company charges a commission of $10 per trade plus $0.025 per dollar value of stock traded. if your commission is $140 , what was the value of the stock you traded?

Value of the stock traded was $5200.

Step-by-step explanation:

In this question it is given that trading company charges commission of $10 per trade or transaction plus $.025 per dollar value of stock.We have to calculate the value of stock we traded if total commission (commission on trade value + commission on trade) is $140.

Let the value of stock traded was $x.

Then commission on value of the stock = x×.025

Commission on transaction = $10

Total commission = 140 = ( .025x + 10)

⇒.025x = 140-10 = 130

x = 130÷.025 = $5200

So the value of the stock = $5200

$5200  

Step-by-step explanation:

Let C = total commission

and d = dollar value of stock

Then

C = 10 + 0.025d

Let C =140

140 = 10 + 0.025d     Subtract 10 from each side

130 = 0.025d               Divide each side by 0.025

  d = $5200

The value of the stock was $5200.

Check:

140 = 10 + 0.025 × 5200

140 = 10 + 130

140 = 140

32

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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