What is the point-slope form of a line that has a slope of 3 and passes through the point (–1, 4)? y  – (–1) = 5(x  – 4)4 –  y1  = 3(–1 –  x1)y  – 3 = –1[(x  – (–4)]y  – 4 = 3[(x  – (–1)]

D

Step-by-step explanation:

The equation of a line in point-  slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 3 and (a, b) = (- 1, 4), hence

y - 4 = 3( x - (- 1)) which simplifies to

y - 4 = 3(x + 1)

D. y-4=3[(x-(-4)]

Step-by-step explanation:

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step-by-step explanation:

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