Asap write the expression as a product of polynomials 1) y(a–c)+5a–5c 2) x(b+c)+3b+3c

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1.   (a-c) (y + 5)

2. (b+c)(x+3)

Discussion:

1.

y(a-c) + 5a - 5c                         => factor 5 from the second expression

= y(a-c) + 5 (a-c)                       => factor (a-c) from each term

= (a-c) (y + 5)

2  

x(b+c) + 3b + 3c                      =>  factor 3 from the second expression

= x(b+c) + 3 (b+c)                    => factor (b+c) from each term

= (b+c)(x+3)

Thank you,

MrB

Answer to Q1

(a-c)(y+5)

Step-by-step explanation:

Given expression is

y(a-c)+5a-5c

we observe that 5 is common in above expression

y(a-c)+5(a-c)

Now, take (a-c) as common

(a-c)(y+5) which is the product of polynomials.

Answer to Q2:

(b+c)(x+3)

Step-by-step explanation:

Given expression is

x(b+c)+3b+3c

3 is common in above factor so ,

x(b+c)+3(b+c)

Now, take (b+c) as common

(b+c)(x+3) which is the product of polynomials.

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step-by-step explanation:

answer: sine

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