Two football players are located at points aa and bb in a rectangular football field as shown at left. point aa is located 5050 yards (\text{yd})(yd) from the west edge and 25 \, \text{yd}25yd from the south edge; point bb is located 12 \, \text{yd}12yd from the east edge and 0 \, \text{yd}0yd from the south edge. what is the distance, in yards, between the two players? (round your answer to the nearest tenth of a yard.)

45.5 yards.

Step-by-step explanation:

We are given that two players are located at the points A and B in the rectangular field.

It is given that,

Point A is located 50 yards from the west edge and 25 yards from the south edge.

Thus, point A is given by the co-ordinate (50,25).

Also, Point B is located 12 yards from the east edge and 0 yards from the south edge.

So, point B is given by the co-ordinate (12,0).

Now, we need to find the distance between the points (50,25) and (12,0).

'The distance between two points and is given by '.

So, the required distance is,

Distance between players =

i.e. Distance between players =

i.e. Distance between players =

i.e. Distance between players =

i.e. Distance between players = 45.5 yards.

Thus, the distance between the two players located at A and B is 45.5 yards.

answer: are you

step-by-step explanation:

this is answer of 144 cubic meters