1point) a function f(x)f(x) is said to have a removable discontinuity at x=ax=a if: 1. ff is either not defined or not continuous at x=ax=a. 2. f(a)f(a) could either be defined or redefined so that the new function is continuous at x=ax=a. let f(x)=⎧⎩⎨5x+−4x+15x(x−3),9,if x≠0,3if x=0f(x)={5x+−4x+15x(x−3),if x≠0,39,if x=0 show that f(x)f(x) has a removable discontinuity at x=0x=0 and determine what value for f(0)f(0) would make f(x)f(x) continuous at x=0x=0. must redefine f(0)=f(0)= -1/5 equation editorequation editor . hint: try combining the fractions and simplifying. the discontinuity at x=3x=3 is actually not a removable discontinuity, just in case you were wondering.

Martha has a deck of cards. she has lost some of the cards, and now the deck only contains nine spades, eleven diamonds, eight clubs, and twelve hearts. martha predicts that whenever she draws a card from the deck without looking, she will draw a club one-fifth of the time. which activity would best allow martha to test her prediction? a. randomly draw a card from the box and see if it is a club. b. randomly draw a card. then, continue to draw another card until all eight clubs are drawn. c. randomly draw and replace a card 120 times. then, observe how close to 30 times a club is drawn. d. randomly draw and replace a card 100 times. then, observe how close to 20 times a club is drawn.