Mr. mole left his burrow that lies 7 77 meters below the ground and started digging his way deeper into the ground, descending at a constant rate. after 6 66 minutes, he was 1 6 1616 meters below the ground. let a ( t ) a(t)a, left parenthesis, t, right parenthesis denote mr. mole's altitude relative to the ground a aa (measured in meters) as a function of time t tt (measured in minutes).

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

from the sentence, "tomorrow morning, akiko will arrive an hour late" depicts a third person perspective because it doesn't use any pronoun to replace akiko, the subject of the sentence, and it is in singular form since akiko is only one person.

what was there favorite food