Ineed to know the values of x that are not in the domain of h.

x = - 7, + 7

Step-by-step explanation:

The denominator of h(x) cannot be zero as this would make h(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be.

solve :

x² - 49 = 0 ⇒ (x - 7)(x + 7) = 0 ⇒ x = ± 7

The domain is valid for all x ∈ R , x ≠ - 7, + 7

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

the correct answer is d

hope this