What is the equation of the line that is parallel to the given line and passes through the point (12, −2)? a. y = -6/5x + 10 b. y = -6/5x + 12 c. y = –5/6x – 10 d. y = 5/6x – 12

D. y = 5/6x – 12

Step-by-step explanation:

Our first step is to determine the slope of the given line.  As we move from (0, -4) to (12, 6), x increases by 12 and y increases by 10.  Thus, the slope is

m = rise/run = 10/12, or m = 5/6.

Answer option D is the only one that has the same slope.  Thus, D is the answer.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

i dont know sorry

step-by-step explanation: