2. solve each given location and show your work. tell whether each equation has one solution, an infinite number of solutions, or no solutions. explain your answers. (a) 4x + 2(x – 1) = 10 + 2x (b) 30 – x = 10 – (6 + 10) (c) 8x = 4x + 4x + 10(x-x) answers:

a  one solutions x=3

b  one solution x=36

c  infinite solutions

Step-by-step explanation:

(a) 4x + 2(x – 1) = 10 + 2x

Distribute

4x+2x-2 = 10+2x

Combine like terms

6x-2 = 10+2x

Subtract 2x from each side

6x-2x-2 = 10+2x-2x

4x-2 = 10

Add 2 to each side

4x-2+2 =10+2

4x=12

Divide by 4

4x/4 = 12/4

x=3

There is one solution

(b) 30 – x = 10 – (6 + 10)

Distribute the minus sign

30-x = 10-6-10

30-x=-6

Subtract 30 from each side

30-x-30 = -6-30

-x = -36

Multiply by -1

x = 36

(c) 8x = 4x + 4x + 10(x-x)

Parentheses first

8x = 4x+4x+10(0)

8x=4x+4x

Combine like terms

8x=8x

Subtract 8x from each side

8x-8x=8x-8x

0=0

This is always a true statement

x =all real numbers

infinite solutions

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

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step-by-step explanation: