Convert the following quadratics from standard form to vetex form, then graph them.1. y=x^2+6x+52. y= -x^2-6x-7

1.  y = (x + 3)² - 4

Step-by-step explanation:

Vertex format is: y = a(x - h)² + k

y = x² + 6x + 5

y - 5 = x² + 6x       subtracted 5 from both sides

y - 5 + = x² + 6x +    completed the square

y + 4 = (x + 3)²        simplified

y = (x + 3)² - 4        subtracted 4 from both sides

Equation is now in vertex form!

To graph the equation, plot the following points:

2.  y = -(x + 3)² + 2

Step-by-step explanation:

Vertex format is: y = a(x - h)² + k

y = -x² - 6x - 7

y + 7 = -x² - 6x       added 7 to both sides

-y - 7 = x² + 6x         divided both sides by -1

-y - 7 + = x² - 6x +    completed the square

-y + 2 = (x + 3)²        simplified

y - 2 = -(x + 3)²        divided both sides by -1

y = -(x + 3)² + 2        subtracted 4 from both sides

Equation is now in vertex form!

To graph the equation, plot the following points:

you cant answer this dummy

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.