The length of a rectangle is 5 centimeters less then twice it's width. the perimeter of the rectangle is 26 cm. what are the dimensions of the rectangle

The dimensions of the rectangle are length = 7cm and width = 6cm.

Step-by-step explanation:

In order to solve for the dimensions, you will need to set up two equations in order to solve for the missing variable.  Given the information that the length is 5 cm less then twice it's width, using 'L' for length and 'w' for width we get the following equation:  L = 2w - 5.  Perimeter is the sum of all the sides, or in the case of a rectangle P = 2w + 2L.  We can then use our expression for 'L' in our perimeter formula:  26 = 2w + 2(2w - 5).  First, using the distributive property we get: 26 = 2w + 4w - 10.  Next, we combine like terms:  26 = 6w - 10.  Then, we use inverse operations to isolate the variable:  26 + 10 = 6w - 10 + 10 to get 36 = 6w, divide both sides by 6 to get w = 6.  Lastly, plug in the value of 'w' to 'L':  L = 2(6) - 5 or L = 7.

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft