To determine the weight of plastic discarded by households, a sample size of 62 weighs ae measured and are found to have a mean of 1.911 lb and a standard deviation of 1.065 lb. construct a 99% confidence interval estimate of the mean weight of plastic discarded by all households

Confidence interval estimate of the mean weight of plastic discarded by all households is : (1.561 , 2.261)

Step-by-step explanation:

Sample size, n = 62

Now the Confidence interval is : Mean ± Margin of Error

                                                     = (1.911 - 0.35 , 1.911 + 0.35)

                                                     = (1.561 , 2.261)

Hence, Confidence interval estimate of the mean weight of plastic discarded by all households is : (1.561 , 2.261)

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560