The ratio of a number and 4 times that number is equal to the ratio of 5 times the number and 95 more than a number i just need the problem

  1/4 = (5n)/(n +95)

Step-by-step explanation:

If all the numbers referred to are the same number, we can use n to represent it. Then, "the ratio of a number and 4 times that number" is n/(4n) = 1/4. "The ratio of 5 times the number and 95 more than the number" is (5n)/(n+95)

The equation for the problem can be written ...

  1/4 = (5n)/(95+n)

___

If you're a purist, you might leave the factors of "a number" in the first raio and write it ...

  n/(4n) = (5n)/(95+n)

Solving this gets you to a quadratic form that has the extraneous solution n=0.

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: