The percent p of the u. s. population with internet access is given by 25p-34t=1378 where t is the number of years after 1990. what percent of the u. s. population had interent access in 2005? (round to one decimal place) in what year will 89% have internent access?

Step-by-step explanation:

the percent p of the u.s. population with internet access is given by:

25 p-34 t=1378

where t is the number of years after 1990.

⇒  25p-34×(15)=1378

⇒  25p-510=1378

⇒  25p=1378+510

⇒  25p=1888

⇒  p=75.52

Hence, 75.52 percent of the u.s. population had internet access in 2005.

i.e. we have to find the value of t when we are given p=89

⇒  25×89-34t=1378

⇒  2225-34t=1378

⇒  2225-1378=34t

⇒  847=34t

⇒  or 34t=847

⇒  t=24.9112≈25

Hence after 25 years 89% will have internet access.

i.e. in the year 2015 89% will have internet access.

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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step-by-step explanation:

it have the same area.brainliest