Need with son's assignment . answer the following questions a. find the perimeter of the square b. find the perimeter of the rectangle c . find the sum of the perimeters of the two figures if s=5 d. the perimeter of the rectangle is greater than the perimeter of the square. find the difference between the perimeter of the two figures if s=7

A. Perimeter of the square = 5s + 2

B. Perimeter of the rectangle = 8s + 8

C. Sum of the perimeters if s = 5:  75

D. Different between the perimeters if s=7:  27

Step-by-step explanation:

This problem is asking you to use expressions to first calculate the perimeters of two figures with a variable expression, then calculating the exact value of the perimeters when given the value of the variable.  For A, the perimeter of a square is the sum of all four sides, since the sides of a square are all equal.  You can find the answer by taking the given expression (5s + 2/4) and multiplying by 4 which gives you 5x +2.  For B, the perimenter of a rectangle is found by again adding up all the sides, however in a rectangle the opposite sides are equal, so the widths and lengths are the same.  In this case, we can take each expression and multiply by 2 and then add them together:  2(s + 9) + 2(3s -5) = 2s + 18 + 6s -10 = 8s +8.  For C, when given the value of s = 5, we can then substitute this number for 's' in both expressions:  5(5) + 2 = 27 and 8(5) + 8 = 48; 27 + 48 = 75.  For D, when given the value of s = 7, we can then subsitute this number for 's': 5(7) + 2 = 37 and 8(7) + 8 = 64; 64 - 37 = 27.

is there answer choices?