For what values of y is the value of the fraction 5−2y 12 greater than the value of the binomial 1−6y?

The question is ambiguous, since it's not clear how we should consider the fraction. Anyway, I see two alternatives:

Multiply both sides by 12:

Add 72y to both sides:

Subtract 5 from both sides:

Divide both sides by 70:

If, instead, you meant

we proceed as follows: subtract 5 from both sides

Switch signs and inequality mark:

Multiply both sides by 12:

Subtract 2y from both sides:

subtract 48 from both sides:

Divide both sides by 70:

For all the values of y>0.1 the fraction is greater than the binomial

Step-by-step explanation:

We have to find the values of y where . The first step we are going to do is multiply by 12 in both sides of the expression.

Now we are going to use distributive property on the right side,

Observation: distributive property: (b+c)a=ba+ca

Then we have to add 72y in both sides.

Now subtract 5 from both sides,

Divide both sides in 70

Then for all the values of y>0.1 the fraction is greater than the binomial

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3