Solving systems of equations using any method

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

 {x = 5 , y = 2

5+2x=a

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