Determine the standard from of the equation of the line that pasees though (0,5 and (4,0)

5x+ 4y =20

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

           = (0-5)/(4-0)

           = -5/4

We know the slope  = -5/4  and the y intercept (x=0)  y= 5

The euqation in slope intercept form is

y=mx+b whre m is the slope and b is the y intercept

y = -5/4 x +5

Multiply each side by 4 to get rid of the fraction

4y = 4*-5/4x + 5*4

4y = -5x+20

Add 5x to each side

5x+4y = 5x-5x+20

5x+ 4y =20

This is the standard form of a line

Ax + By =C

The standard form:

The slope-intercept form:

m - slope

b - y-intercept → (0, b).

The formula of a slope

We have the points (4, 0) and (0, 5) → y-intercept → b = 5.

Calculate the slope:

Therefore we have:

     multiply both sides by 4

       add 5x to both sides

a negative exponent is translated as follows:

so, we have