Factor the following trinomial 3x^2+10x+8

(x + 2)(3x + 4)

Step-by-step explanation:

Consider the product of the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term, that is

product = 3 × 8 = 24 and sum = 10

The factors are + 6 and + 4

Use these factors to split the middle term

3x² + 6x + 4x + 8 (factor the first/second and third/fourth terms )

= 3x(x + 2) + 4(x + 2) ← take out the common factor (x + 2)

= (x + 2)(3x + 4) ← in factored form

597

step-by-step explanation: