Ken paid for $12 for two magazines. the cost of each magazine was a multiple of 3. what is mare the possible prices of the magazines?

So the possibilities are

$12 and $ 0    ,    $9 and $ 3      , $6 and $6

Step-by-step explanation:

Given:

Total Magazines = 2

Price = $ 12

To Find:

Possible Prices of magazines = ?

Solution:

As it is given that Prices of magazines is multiples of 3

So

Multiples of 3 up till 12 are  

0, 3 , 6 , 9 , 12

Now

Total Price of magazine is $12

Now The possible prices of the magazines are

First Possibility:

If price of first magazine is $12 then second would be $0 (free)

First possible price $12 and $0

Second Possibility:

If price of first magazine is $9 then second would be $3

Second possible price $3 and $9

Third Possibility:

If price of first magazine is $6 then second would be $6

Third possible price $6 and $6

So the possibilities are

$12 and $ 0    ,    $9 and $ 3      , $6 and $6

well

44-3-3-3=35

35+4+4+4+4=51

so the ansewr would be 51 degreesat 7: 00