Afruit stand has to decide what to charge for their produce. they need \$10$10 for 44 apples and 44 oranges. they also need \$15$15 for 66 apples and 66 oranges. we put this information into a system of linear equations. can we find a unique price for an apple and an orange?

We can't find a unique price for an apple and an orange.

Step-by-step explanation:

Suppose, the price of an apple is and the price of an orange is

They need $10 for 4 apples and 4 oranges. So, the first equation will be.......

They also need $15 for 6 apples and 6 oranges. So, the second equation will be........

Dividing equation (1) by 2 on both sides :  

Dividing equation (2) by 3 on both sides :  

So, we can see that both equation (1) and (2) are actually same. That means, we will not get any unique solution for and here. Both and have "infinitely many solutions".

Thus, we can't find a unique price for an apple and an orange.

The answer has no solutions

Step-by-step explanation:

As the other person said there were infinity solutions, it was as the opposite. There is no rational answer for this, but the answer is no solutions.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse