Lots of points pls becky wants to fence in a rectangular play area for her dog. if she has 82 feet of fencing and wants the length of the play area to be 9 feet longer than its width, what should the dimensions of the play area be?

form 2 equations

length=x

width=y

the equations are:

2(x+y)=82, because 82 would the the perimeter which is 2(l+w)

x=y+9

Now use substitution and you'll get y=16. Then plug in 16 and you'll get x=25. so the length is 25 and the width is 16.

Therefore the dimensions would  be 25 by 16. Notice that the length, 25, is 9 greater than the width, 16. Also notice that a perimeter of a rectangle with length 25 and width 16 is 82 ( 2(25+16)=2(41) = 82))

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions