Ax^3 -7x^2 + 7x-2, x^3 -2ax^2 +8x-8. i’m to solve for a, and know that when both equations are divided by x-2 they leave the same remainder. so far i’ve verified through synthetic division that they do indeed leave the same remainder, not , but it’s what i have so far. some insight would be appreciated.

Maybe an easier way to do it is to apply the polynomial remainder theorem. It says that dividing a polynomial by leaves a remainder of .

In this case, , and we have

Then

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4