When x=−1 and y=−2 , how do the two expressions compare? when x= -1 and y= -2 => < 3x−y2 (x+y)2+y

Step-by-step explanation:

3(-1) - (-2)2 = (-1 + (-2))2 + (-2)

-3 - (-4) = (-1 - 2)2 - 2

-3 + 4 = (-3)2 - 2

1 = -6 - 2

1 = -8

Their answer is different after substitution.

3x - y2 has an answer that is 1 while (x + y)2 + y has an answer of -8.

(x + y)2 + y does not have a 3 in it like the first equation 3x - y2.

x and y are in parentheses in (x + y)2 + y and the equation 3x - y2 aren't.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option