Abag contains, red, blue and yellow balls the probability of picking a red ball is 1/3 the probability of picking a blue ball is 1/5 a.) work out the probability of picking a yellow ball b.) there are 10 red balls how many balls are there in total c.) grace adds 10 balls to the bag so that: p(red) = 1/4 and p(blue) = 2/5 how many of each color does she add space out your answer and label 'a' 'b' and 'c'

a)

b) There are 30 balls

c) Number of blue balls added = 10, number of red balls added = 0 and number of yellow balls added = 0

Step-by-step explanation:

a) Sub of the probabilities is always 1.

Therefore,

p(red) + p(blue) + p(yellow) = 1

b) p(red ball) =

But, it is given that n(E) = 10

Therefore,

n(S) = 30

Hence, there are 30 balls in total

c) From b), there are 10 red balls.

Now, p(blue ball) =

Since, n(S) = 30,

n(E) = 6

There are 6 blue balls and

the number of yellow balls = 30 - (10 + 6) = 14

After adding 10 balls, n(S) = 40

p(blue ball) =

= 16

But, number of blue balls before addition = 6.

Hence, all the added balls are blue.

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5