Solve x2+12x=-11 by completing the square . which is the the solution set of the equation?

{- 11, - 1 }

Step-by-step explanation:

Since the coefficient of the x² term is 1 , to complete the square

add (half the coefficient of the x-term )² to both sides

x² + 2(6)x + 36 = - 11 + 36 ← complete the square on the left side

(x + 6)² = 25 ( take the square root of both sides

= ±

x + 6 = ± 5 ( subtract 6 from both sides )

x = - 6 ± 5

x = - 6 + 5 = - 1 or x = - 6 - 5 = - 11

{- 11, - 1 }

Step-by-step explanation:

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

-3(b-8)-5=9(b+2)+1

distribute

-3b+24-5=9b+18+1

add/ subtract

-3b+20=9b+19

20-19= 1

-3b+1=9b

9b+3b= 12b

1=12b

1 divided by 12 = 1/12

answer: 1/12 = b