One computer processes a company's payroll in 20 minutes. while another computer takes 32 minutes. how long would it take in minutes to process payroll if both computers were used?

Time taken would be = 12 minutes to print the payroll if both computers are used

Step-by-step explanation:

Computer A Takes = 20 minutes

Computer B Takes = 30 minutes

To Find:

Time to print if both were used = ?

Solution :

Now We will first calculate How much work is done by each computer in one minute

Computer A will do = 1/20 Work one minute

Computer B will do  = 1/30 work in one minute

Now if both computers are used then

work done by both of them in one minute would be sum of both the computers f the work together

So

it would be

Work done =

Taking LCM and solving

Work done =

                   =

                   =

Now to do the whole task Time taken would be reciprocal of Work done in one minute

So

Time taken would be = 12 minutes

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3