If the radius of the base of the cone is 8/3 units and the height is 12 units, what is the volume?

256/9 * pi  units ^3

or approximately

89.3608577021096743  units^3

Step-by-step explanation:

V = 1/3 pi r^2 h

where r is the radius and h is the height

V = 1/3 * pi * (8/3) ^2 * 12

   = 1/3 * pi * 64/9 * 12

      256/9 * pi  units ^3

or approximately

89.3608577021096743  units^3

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.