Anybody care to me figure this out properly, the lesson did not give me enough infogiven the system of linear equations part a: graph the system of linear equations. part b: use the graph created in part a to determine the solution to the system. part c: algebraically verify the solution from part b.

I, personally, have two favorite ways to solve system of equations.

The first, is substitution. Substitution is where you place a known variable from one equation into the other. In this case, the known variable is y=-5. I will 'substitute' the y=-5 into the y=3x-2

y=3x-2

(-5)=3x-2

-5=3x-2

-3=3x

x=-1

Now we know the x and y value!

(-1,-5)

The second way is much quicker, but isnt always accessible, and that way is graphing. I have attached a graph

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says