Which statement is true about f=(x)=-2/3|x+4|-6 ?

The graph of f(x) has domain of x<=-6

Step-by-step explanation:

Given function is

compare this formula with f(x)=a|x-h|+k, we get h=-4, k=-6

We know that vertex for above formula is given by (h,k) then vertex for given function will be (-4,-6)

which is different than given choice so first choice is not possible.

We see that 2/3 is multiplied outside of the parent function |x| so that will create vertical not horizontal compress so 2nd choice is wrong.

when value of a is positive the graph opens up. But we have a=-2/3 which is negative so graph will open down. Hence 3rd choice is wrong.

Absolute function will have domain, all real number so x<=-6 is part of that which is partially correct.

So 4th choice seems more accurate than others.

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week