In a radioactive substance half-life is 40 years about how much of a 30g sample was left after 160 yearsa 1.9b 3.8c 7.5d 15

A 1.9

Step-by-step explanation:

Nt = No e^(-kt)

Where Nt is the ending amount

No is the starting amount

k is the decay constant

and t is the time

We need to determine the half life

Nt/No = e ^ -kt

1/2 of the original amount is left  for 1/2 life.  The time is 40 years.  We will calculate k

1/2 = e ^ -k * 40

Take the natural log of each side

ln(1/2) = ln (e ^ -k * 40)

ln (1/2) = -40k

-ln(2) = -40k

ln 2 = 40k

1/40 ln (2) = k

Now we can calculate now much is left after 160 years of a 30 g sample

Nt = 30 e^(- 1/40 ln(2) * 160)

    = 30 e^(-4ln(2))

    = 15/8

       =1.875

d

step-by-step explanation:

d

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i