Let $g(x)$ be a function piecewise defined as \[g(x) = \left\{ \begin{array}{cl} -x & x\le 0, \\ 2x-41 & x> 0. \end{array} \right.\] if $a$ is negative, find $a$ so that $g(g(g(10.=g(g(g($.

Since , we have .

Since , .

Meanwhile, , and , and .

So we want to find such that .

Suppose , which happens if . Then , so that . But -21 is smaller than -20.5, so there's a contradiction.

This means we must have , which occurs for . Then , so that .

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

answer: i'm great at algebra

~coco

step-by-step explanation: