Find the area of a square with a side measure of 3x − 6 feet. question 5 options: 9x2−36x+36 sq. ft. 9x2−6 sq. ft. 9x2+36x+36 sq. ft. 9x2+36 sq. ft.

Area of a square: s^2

Because we know the length of one side, we can multiply it by itself to find the area.

(3x - 6)(3x - 6)

9x^2 - 18x - 18x + 36

Combine like terms.

9x^2 - 36x + 36

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

a and c

step-by-step explanation: