The polynomial x 3 + 5x 2 - ­57x -­189 expresses the volume, in cubic inches, of a shipping box, and the width is (x+3) in. if the width of the box is 15 in., what are the other two dimensions? ( hint: the height is greater than the depth.)

The other two dimensions are either (x+9) or (x-7). other two dimensions are either 21 inches  or 7 inches.

Step-by-step explanation:

The volume is defined by the function.

The width is (x+3).

Using synthetic or long division method divide by (x+3).

The volume of cuboid is

Therefore other two dimensions are either (x+9) or (x-7).

If the width is 15 inches, then

The other two dimensions are

Therefore other two dimensions are either (x+9) or (x-7). other two dimensions are either 21 inches  or 7 inches.

Other two dimensions are 21 and 5.

Height = 21 in.

Depth = 5 in.

Step-by-step explanation:

Since we have given that

As we have given that

Width = x+3

That means

So, by dividing, x^3 + 5x^2 -57x-189 by x+3 we get,

Noe, we split the quadratic equation:

So, as we have given that

Width = 15

So, other two dimensions are 21 and 5.

Height = 21 in.

Depth = 5 in.

hello!

some people may think so but i don't. its just a human instinct in my opinion.

have a fantastic day! ~pooch ♥

we know that

major arc is defined as the bigger arc connecting two points on the edge of a circle. measure of major arc is always more than ° or π radian

in this problem

the mayor arc is bac

find the ratio of the measure of the major arc to the measure of the minor arc

therefore

the answer is the option